What type of isomers are the following two compounds?They do not seem to be geometrical isomers as the methyl groups at terminal position are not in same plane as such.Are they conformers?

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    $\begingroup$ Believe it or not, they are enantiomers. Oh, and you don't normally draw them like that, because like you said, those methyls are out of plane. $\endgroup$ – Ivan Neretin Aug 10 '16 at 5:44
  • $\begingroup$ Could you explain a bit more elaborately if you have time?Thanks. @IvanNeretin $\endgroup$ – user14857 Aug 10 '16 at 5:47
  • $\begingroup$ @IvanNeretin I did'nt draw them :-P! $\endgroup$ – user14857 Aug 10 '16 at 5:48
  • $\begingroup$ Then these pictures are meaningless and don't represent anything. Or, if we put it another way, they are poorly drawn pictures of the same compound (like in @julien's answer), which, BTW, exists as a pair of enantiomers, but the pictures don't tell you which is which. $\endgroup$ – Ivan Neretin Aug 10 '16 at 5:50
  • $\begingroup$ @IvanNeretin Oh well I think I understood why they are enantiomers! $\endgroup$ – user14857 Aug 10 '16 at 5:51

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