1
$\begingroup$

Theoretically it is said that the compound can show oxidation states in the interval $[n,n-8]$ where $n$ is the number of valence electrons.

Is there any compound in which oxygen shows +1/2 oxidation state. If so, then please provide an example.

$\endgroup$
3
  • 6
    $\begingroup$ $\ce{O2+[PtF6]-}$ is an example. $\endgroup$ Commented Jul 10, 2016 at 15:54
  • 3
    $\begingroup$ And a famous one at that. Its synthesis heralded the similar synthesis with $\ce{Xe}$ in place of molecular oxygen, and thus the coming of noble-gas chemistry. $\endgroup$ Commented Jul 16, 2016 at 0:18
  • 1
    $\begingroup$ The rule doesn't work with d-elements that good. FYI, Mn shows oxidation states -3 ... +7 afaik except -2 and for Iridium it's -3..+8 .... $\endgroup$
    – permeakra
    Commented Aug 9, 2016 at 18:56

1 Answer 1

3
$\begingroup$

Yes. The dioxygenyl ion, $\ce{O_{2}^+}$, is a rarely-encountered oxycation in which both oxygen atoms have a formal oxidation state of +1/2. It is formally derived from oxygen by the removal of an electron:

$$\ce{O_{2} → O_{2}^+ + e^{-}}$$

Source

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.