This question came in an online test, where they asked whether or not 22,26-dibromo-12,32-dichloro-23,25-diiodo-16,36-dimethyl-11,21:24,31-terphenyl was optically active. (The answer is that it is optically active)
According to Solomon and Fryhle: "Biphenyl is an asymmetric compound so it must not have a plane of symmetry or center of symmetry to be optically active". Hence compounds which have 2 same adjacent groups on a single phenyl in any biphenyl system cant be considered optically active .
Applying that concept above as same groups (Br and I) are attached to the middle phenyl system, the individual biphenyl systems on both sides are optically inactive, hence the compound is optically inactive.
Please tell me where I am going wrong in my interpretation.