# Do I need to include calcium chloride in this reaction equation?

Yesterday I titrated a solution of calcium hydroxide in aqueous calcium chloride with $16.7~\mathrm{mL}$ of $\ce{HCl}$. More specifically, I took $25\ \mathrm{mL}$ of the calcium hydroxide in aq calcium chloride and mixed it with $25~\mathrm{mL}$ of deionized water and 3 drops of an appropriate indicator. I wrote the reaction equation as

$$\ce{Ca(OH)_2 + 2HCl -> CaCl_2 + 2H_2O}$$

But do I need to somehow take into account the aqueous calcium chloride in this equation? I know that it affects the molar solubility of the calcium hydroxide during titration but I'm not sure if this should also change my reaction equation.

• Is it a reactant? Does it react with the other substances? – Archa Jun 30 '16 at 16:33
• Hmmm...not sure. We did 2 experiments where the only difference was the original solution: exp #1 used calcium hydroxide and exp #2 used calcium hydroxide in aqueous calcium chloride. Everything else was the same. – whatwhatwhat Jun 30 '16 at 16:34
• My guess would be no. – whatwhatwhat Jun 30 '16 at 16:36
• @Archa am I right? – whatwhatwhat Jun 30 '16 at 17:42