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This is balanced equation of fermentation of glucose:

$$\ce{C6H12O6(aq) -> 2C2H5OH(aq) + 2CO2(g)}$$

I know that the result of glucose fermentation is ethanol ($\ce{C2H6O}$). What represented in the aforementioned equation is slightly different. I would like to know what $\ce{C2H5OH}$ is?

What is the OH functional group doing here? Does it make ethanol acidic? Does it mean that ethanol is diluted with water?

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It is better to write $\ce{C_2H_6O}$ as $\ce{C_2H_5OH}$, because there is more than one compound with the same overall formula, and emphasising the hydroxyl group $\ce{-OH}$, which is what characterizes an alcohol makes it ethanol and nothing else. So when you ask, "What is OH functional group doing here", it is exactly that the product is an alcohol, characterized by a hydroxyl group. And yes, alcohols are acidic in the right situations, given that their hydroxyl groups do produce acidic hydrogen ions, and yes, that is why it's so soluble in water.

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I confused compound formula with the actual formula of ethanol. Compound formula is $\ce{C2H6O}$. But the actual molecular structure is $\ce{CH3CH2OH}$. The oxygen is attached to hydrogen which it in turn is attached to Carbon.

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