I'm given the following details:

  • $m$(salt) = 100g;
  • $V$($\ce{H2O}$) = 500ml;
  • $D$($\ce{H2O}$) = 1g/ml;

The question is what is the mass fraction of salt in a mix of $\ce{H2O}$ and salt?

In order to find out the answer I first use the formula $$ V = \frac{m}{D} \ce{->} m(\ce{H2O}) = 500\text{g}; \quad w(\text{salt}) = \frac{m(\text{salt})}{m(\ce{H2O})+m(\text{salt})} $$

Eventually $w(\text{salt})$ turns out to be 1/6. Are my calculations true ?

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I believe they are correct.

You have 500g of water and add 100g of salt. The total mass is 600g, So the mass fraction of salt is 1/6.

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  • 1
    $\begingroup$ What made you think your calculations were not correct in the first place ? $\endgroup$ – An intern has no name Jun 16 '16 at 10:14

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