3
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Compound

Does this structure show aromaticity? Or does this not work with nitrogen?

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  • $\begingroup$ Mm, oxygen radicals... is that an OH group? $\endgroup$ – orthocresol Jun 13 '16 at 8:40
  • $\begingroup$ Yes, sorry my bad. That's an OH group $\endgroup$ – 4C0G Jun 13 '16 at 8:46
  • $\begingroup$ What's wrong about nitrogen? Pyridine is aromatic, so is pyrimidine, hence so should be your compound, once you fix that issue with O. $\endgroup$ – Ivan Neretin Jun 13 '16 at 8:47
3
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Each Nitrogen has 5 valence electrons. They are using 2 of those in sigma bonds to their neighbouring atoms, 2 in an sp2 lone pair in the plane of the ring, leaving only 1 electron to contribute to the delocalised pi system.

Each carbon is also contributing 1 electron to the delocalised pi system, and has 3 involved in sigma bonds.

This means each member of your 6 membered ring is contributing 1 electron, 6 in total. This means it is aromatic, as all 3 bonding orbitals are fully occupied.

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