Devarda's alloy is used in the detection of nitrates. However, judging by the reaction equation, only aluminium plays the role of reducer:

$$\ce{3NaNO3 + 8Al + 5NaOH + 18H2O -> 8Na[Al(OH)4] + 3NH3(g)}$$

Why does it contain copper? Is copper also capable of acting as a reducer here?

I know that zinc, the third component, is capable of that.

  • 4
    $\begingroup$ Galvanic couple, I guess. $\endgroup$ – Ivan Neretin May 25 '16 at 15:23
  • 4
    $\begingroup$ Catalyst, I guess. ;-) $\endgroup$ – aventurin May 25 '16 at 15:30
  • 5
    $\begingroup$ Blessed be the guessers, for they lead us to understanding. $\endgroup$ – CowperKettle May 26 '16 at 6:13

Virtually every analytical chemistry textbook's chapter on anion determination mentions that Devarda's alloy is very brittle and can be easily pulverized in a mortar, unlike $\ce{Al}$ and $\ce{Zn}$ metals. This is quite handy property as for qualitative analysis of nitrates in a heterogeneous media the reducing phase should be ground to fine powder in order to:

  1. assure micro-scale precision of the added reactant, which is tricky to achieve with aluminium or zinc, as both metals are usually shipped in granules, and the fine metal powders are prone to oxidation, increasing the amount of unwanted oxides (plus, their powders are sticky);
  2. increase the available reaction surface to speed up the analysis and increase its completeness (especially important for isotopic nitrate analysis).

On top of that, German Wikipedia also supports both comments by Ivan Neretin

Galvanic couple, I guess.

and aventurin

Catalyst, I guess. ;-)

and suggests that copper facilitates catalytical formation of a local electrochemical cell. A reduction with Devarda's alloy can be carried out in weakly alkaline solution or even in neutral solution, whereas reduction with aluminum often requires a strongly alkaline solution. At the same pH, the reaction with Devarda's alloy is overall significantly faster than when using zinc or aluminum.

This was experimentally demonstrated by Mertens et al. [1]:

The superiority of Devarda alloy compared to aluminum dust as a reductant in alkaline medium is illustrated best with the following experiment (see Figure 3). Twenty ppm $\ce{NO3-}$ is subjected to reduction, first with aluminum dust and the potential of the ammonia probe is recorded continuously. One observes a slowly rising potential. On addition of Devarda alloy to this reaction mixture, a potential jump is obtained and the potential stabilizes rapidly (after 5 minutes). This shows clearly that the kinetics of the reduction with Devarda alloy are much more rapid than with aluminum dust.

Figure 3
Figure 3. Potential observed with the ammonia probe during the reduction of 20 ppm $\ce{NO3-}$ as a function of time
From $t = 0$ to A: aluminum dust. At point A, Devarda alloy was added.


  1. Mertens, John.; Van den Winkel, Pierre.; Massart, D. L. Determination of Nitrate in Water with an Ammonia Probe. Anal. Chem. 1975, 47 (3), 522–526. DOI: 10.1021/ac60353a009.
| improve this answer | |
  • 8
    $\begingroup$ Blessed be the commenters for they lead us to an answer after 3.5 years ;) $\endgroup$ – Nilay Ghosh Dec 28 '19 at 17:43

More recent science (as compared to 1975), the action of Al with NaOH is believed to produce surface absorbed hydrogen atoms on the aluminum. Related chemistry is commonly employed via the vigorous action of HCl on Zn (so one of the roles of zinc is to provide added surface area, which may be acted upon by NaOH also, to answer a posited question).

More precisely on the referenced surface chemistry, let me quote from this 2008 doctoral thesis " Alkaline dissolution of aluminum: surface chemistry and subsurface interfacial phenomena" by Saikat Adhikari, as an example:

Hydrogen embrittlement, a process in which brittlement and subsequent cracking of metals is caused by ingress of atomic hydrogen into the metal, is also sometimes thought of as a type of stress corrosion cracking. Due to the detrimental effects of such corrosion processes, it is important to have a fundamental understanding of associated alkaline or acidic dissolution mechanisms.

And more directly:

Apart from activation of the surface, dissolution of aluminum in alkaline solutions at open-circuit also leads extremely high rates of H-absorption into the metal, [9-14] and also formation of nanoscale voids or hydrogen bubbles [15, 16] near the aluminum surface.

H-absorption on the Aluminum surface is a source of hydrogen radicals, •H, which could engage in a stepwise breakdown of nitrate to ammonia. For example, with the nitrate ion a radical reaction:

$\ce{•H + NO3- ⇌ •OH + NO2-}$

$\ce{•H + •OH -> H2O}$

As: e- + H+ ⇌ •H, the net of the above two reactions can be written as (source, see Section Summary of Properties) the following cited reaction for the first stage creation of nitrite:

$\ce{NO3- + 2 H+ + 2 e- -> NO2- + H2O}$

My experience with just alkaline Al is that it is apparently difficult to stop the reaction at the point of just nitrite creation only, by say limiting the amount of aluminum.

So we have a complex reaction system involving surface chemistry, and in the presence of other metals (like copper), a galvanic cell (which implies two different metals, namely Zn and Cu, to answer a second question) introducing solvated electrons, which may push the equilibrium below to the right: $$ e-(aq) + H3O+(aq) ⇌ •H (aq) $$ promoting hydrogen radicals. The latter could explain the acceleration in the breakdown of nitrate (as reported).

Interestingly, one may assume that the •H radical functional behaves (per its seemingly reversible formation reaction: e- + H+ = •H ) as apparently a (e-, H+) pair acting on ions. For an example from 'Hydrometallurgy 2008: Proceedings of the Sixth International Symposium', p. 818, a commercial reductive leaching application citing the reaction (based on surface-treated Aluminum) to quote:

" PbS + 2 •H = Pb + H2S (5) "

Source reference for the above.

which I view functionally as follows:

Pb(+2)S(2-) + 2 (e-, H+) = Pb + H2S (g)

Further, I do NOT recommend experimenting with Al/NaOH in the presence of impurities in a chemistry class. To quote from Bretherick, Volume 1, page 23-24:

A student mixed aluminum foil and drain cleaner in a soft drink bottle, which started emitting gas. Another student carried the bottle outside and was claimed to have been overcome by the toxic fumes [1]. Most drain cleaners are alkalis, so that aluminum will dissolve to produce hydrogen. The bleach that it is is suggested may have been present will produce no toxic fumes in alkali, and one would be surprised to find arsenic or antimony compounds present. If the collapse was not purely hysterical, the remaining, though remote, possibility would be phosphine. The soft drink the bottle had contained was one of the many perhaps best described as impure dilute phosphoric acid [2]. "

| improve this answer | |
  • $\begingroup$ I suspect that the fumes coming from the Al foil and drain cleaner were a mist of H2O and NaOH, possibly with some NH3. Drano consists of NaOH plus aluminum and other stuff, including NaNO3 (to reduce H2 gas production). The nitrate can be reduced to NH3. A soft drink bottle (1-2 L?) with ~200 mL H2O and a lot of Al foil and Drano will create a lot of heat and H2 and mist, and NH3 would be scary - but it is all much safer if done on a small scale to see how fast the reaction goes. And in an open space, with ventilation. $\endgroup$ – James Gaidis Jan 15 at 15:28
  • $\begingroup$ No, per the dialogue, possible mention of PH3 from the phosphate-rich drink, which parallels the breakdown of nitrate to NH3 ! $\endgroup$ – AJKOER Jan 15 at 16:07
  • $\begingroup$ I am referring to the unintentional formation of lethal compounds from miscellaneous salts interacting with the hydrogen radical. Per the hydrometallurgy example, sulfides can introduce H2S. More generally and problematically, salts of Hydroarsenic acid (arsenical analogue of phosphoric acid), for example, could produce deadly Arsine (AsH3),... $\endgroup$ – AJKOER Jan 15 at 16:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.