My teacher told me about resonance and explained it as different structures which are flipping back and forth and that we only observe a sort of average structure. How does this work? Why do the different structures not exist on their own?


This answer is intended to clear up some misconceptions about resonance which have come up many times on this site.

Resonance is a part of valence bond theory which is used to describe delocalised electron systems in terms of contributing structures, each only involving 2-centre-2-electron bonds. It is a concept that is very often taught badly and misinterpreted by students. The usual explanation is that it is as if the molecule is flipping back and forth between different structures very rapidly and that what is observed is an average of these structures. This is wrong! (There are molecules that do this (e.g bullvalene), but the rapidly interconverting structures are not called resonance forms or resonance structures.)

Individual resonance structures do not exist on their own. They are not in some sort of rapid equilibrium. There is only a single structure for a molecule such as benzene, which can be described by resonance. The difference between an equilibrium situation and a resonance situation can be seen on a potential energy diagram.

Potential energy diagrams for norbornyl cation

This diagram shows two possible structures of the 2-norbornyl cation. Structure (a) shows the single delocalised structure, described by resonance whereas structures (b) show the equilibrium option, with the delocalised structure (a) as a transition state. The key point is that resonance hybrids are a single potential energy minimum, whereas equilibrating structures are two energy minima separated by a barrier. In 2013 an X-ray diffraction structure was finally obtained and the correct structure was shown to be (a).

Resonance describes delocalised bonding in terms of contributing structures that give some of their character to the single overall structure. These structures do not have to be equally weighted in their contribution. For example, amides can be described by the following resonance structures:

Resonance forms of acetamide

The left structure is the major contributor but the right structure also contributes and so the structure of an amide has some double bond character in the C-N bond (ie. the bond order is >1) and less double bond character in the C-O bond (bond order <2).

The alternative to valence bond theory and the resonance description of molecules is molecular orbital theory. This explains delocalised bonding as electrons occupying molecular orbitals which extend over more than two atoms.

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    $\begingroup$ Since it came up, here is a nice question about fluoro bullvalene. It should also be noted, that MOT and VBT are congruent theories, at their theoretical limit (exact treatment) they become identical. $\endgroup$ – Martin - マーチン May 23 '16 at 17:13
  • $\begingroup$ @Martin-マーチン What if we measure the position of an electron in a molecule? There will be some uncertainty, but what if we are able to find some position(small finite volume of space in some part of the molecule) of the electron, won't it suggest that the "electron is whizzing around the molecule"? (I've not yet studied quantum mechanics; I'm ready to delete this comment if it's rubbish) $\endgroup$ – Apoorv Potnis Feb 7 '18 at 16:00
  • $\begingroup$ @ApoorvPotnis That is not possible. Electrons behave like particles and waves, it is that duality, among others, that make your suggestion impossible. $\endgroup$ – Martin - マーチン Feb 7 '18 at 16:26
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    $\begingroup$ @ApoorvPotnis Yes, let's say you measure the position of the electron. Now what? Resonance forms do not exist; that does not mean that electrons in the resonance hybrid just "sit" happily at one point in space forever. An electron always has a wavefunction and as such you can theoretically always measure a position or momentum. That is not relevant to the question, which is whether the system is described by 1 wavefunction (i.e. figure (a), a resonance hybrid) or ≥2 wavefunctions (i.e. figure (b) above, rapid interconversion, not resonance) ... $\endgroup$ – orthocresol Feb 7 '18 at 22:17
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    $\begingroup$ @orthocresol I think that I should wait until I learn quantum mechanics fully. Only then, I'll have a clear understanding. $\endgroup$ – Apoorv Potnis Feb 8 '18 at 5:59

Bon has a very nice example of motion potentially restricted because of a barrier, and although it turns out that this is not the case for the norbornyl cation, there are simpler examples that do show inversion through a barrier, such as ammonia inversion or cyclopentene ring puckering. The two structures either side of the barrier would be not be called resonances any more that one would cis or trans isomers, where the barrier is substantial. The time to move back and forth across the barrier can be measured spectroscopically; in the case of $\ce{NH3}$ inversion this is only a few picoseconds.

The theoretical idea of resonance is only necessary to perform an accurate calculation in the valence bond method. In benzene, for example, the three double bonds can be drawn in different ways by rotating them around the ring. But there are other 'resonance' structures that could be added, for example a biradical structure such as the following:

Biradical resonance structure for benzene

and so on. The more of these we add the better the calculation should become. So the resonance is just a way of figuring out what structure to add into our calculation. We could end up with one electron on each carbon, or +/- charges here and there etc. All very high energy structures no doubt, but it may still be necessary for them to be included in a calculation although their contribution may be small. However, there is no suggestion of any conversion between them; they merely form a 'basis set' from which to perform the calculation.


Resonating structures are totally imaginary structures as they are only used to explain the properties of a single molecule. There are no concrete experiments to prove the real existence of resonating structures. But the resonance hybrid has real existence.

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    $\begingroup$ This doesn't really add anything to what has already been said. $\endgroup$ – bon Jul 8 '16 at 20:24
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    $\begingroup$ Nevertheless, it answers the main question, so no flagging or deleting. $\endgroup$ – M.A.R. ಠ_ಠ Jul 8 '16 at 20:33

What my professor tells me about this is that chemists may have made this just for explaining the following facts:

  • In benzene, or chloro-benzene for that matter, the single bond length is shorter than the average value, and the double bond length is somewhat larger than the standard value.
  • A possible explanation for this maybe that a double bond develops a single bond character and vice-versa.
  • Now, to make it sound more scientific (or more chemistic) the respective chemists tried to explain this using the concept of resonance, and it sounded to be sane, as one can visualize electrons (pi-electrons in the case of benzene) to be moving around in order to stabilize the whole compound, which also made sense from that basic principle of chemistry that everything, EVERYTHING that happens, happens in the direction in which more stability is achieved).
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    $\begingroup$ There are no double and single bonds in benzene so it is meaning to talk about the double and single bond length. All the C-C bonds are the same length. $\endgroup$ – bon Feb 8 '18 at 12:56
  • $\begingroup$ sorry bon, i really gotta brush up on my concepts. $\endgroup$ – Amap Feb 8 '18 at 13:02

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