In paper chromatography, we see that a paper with an ink spot on it get dissolved in the liquid and travels up with water due to capillary action. Then the compounds with more affinity to the paper get deposited on the paper. My question is why do the molecules with more affinity to the paper move with the liquid in the first place and then ultimately settle down after some time?


Chromatography only works when the affinity for the paper vs. affinity for the water is in a dynamic equilibrium. Suppose there are three compounds in the ink, called $\ce{I}$, $\ce{N}$, and $\ce{K}$. Lets call the spots on the paper fiber that bind ink molecules as $\ce{P}$. Then let's write the dyanmic equilibria this way:

$$\ce{I(aq) + P <=>> PI} $$ $$\ce{N(aq) + P <=> PN} $$ $$\ce{K(aq) + P <<=> PK} $$

This means that any given $\ce{I}$ molecule will be absorbing to paper, then becoming unstuck from the paper, then absorbing to a (probably different) site on the paper, then desorbing again and returning to aqueous solution. The same is true of $\ce{N}$ and $\ce{K}$.

There are two further facts that we need to realize to understand the chromatography. The first is that the equilibria are balanced at different points. This is why the size of the arrows in the reactions I drew above are different. As drawn, component $\ce{I}$ has stronger affinity for the paper and a lesser affinity for water, as indicated by the longer rightward top arrow and the shorter bottom left arrow. The reverse is true for component $\ce{K}$, and $\ce{N}$ is somewhere in between.

The second fact is that the water is moving due to the capillarity you mentioned. So when the compounds are in aqueous solution, they will flow with the water. When they are stuck to the paper, they will not move. Since all of the molecules are very rapidly transitioning between paper-bound and water-"bound" states, they will all move some of the time, and be still another part of the time. The key is that the different components spend, on average, different fractions of time moving vs. being still. This makes their average speed different.

As for the question of why they eventually come to rest, this is because the capillarity-driven flow eventually runs out of steam (i.e. gravitational forces compete with the capillary forces after the fluid rises far enough), and the water itself stops flowing very much. Thus the bands of separated molecules eventually settle into a relatively fixed position.

So to answer your title question, truly insoluble compounds would not be separated by chromatography. Compounds need to be soluble to at least a degree in order to be separated.

| improve this answer | |
  • $\begingroup$ That would mean that the compounds which are a little soluble in water would move along with water. Why would a substance with greater affinity to the paper move with the solvent altogether? Shouldn't they all keep sticking to the paper on account of being more attracted to the paper? @Curt F. $\endgroup$ – user29898 May 13 '16 at 11:13
  • $\begingroup$ Also, as the water ascends, the insoluble compounds of water are not able to keep pace with water's speed whereas the soluble compounds move higher up because of the kinetic energy provided by water. Now as the portion of water level that is "moving" exceeds the insoluble compounds, the insoluble compounds are left in the portion of water which is not really moving, thus their kinetic energy further decreases and they eventually come to a stop.- does this explanation make sense? @Curt F. $\endgroup$ – user29898 May 13 '16 at 11:27

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.