I'm a chemistry school teacher.

I want to know how to recover lead Nitrate from the ppt of PbI2.

I know I can do it using conc HNO3 but I do not know if NO or HI will form. Also I would need a guide on the conditions of the reaction.

I don't want to dispose the lead if I can avoid that.

Thank you


The reaction is given here.

$$\ce{3PbI2 + 8HNO3 ->[\Delta] 3Pb(NO3)2 + 3I2 + 2NO + 4H2O}$$

Lead(II) iodide react with nitric acid to produce lead(II) nitrate, iodine, nitrogen monoxide and water. Nitric acid - 30% solution. The reaction takes place in a boiling solution.

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