What I know is, that in a substitutional alloy, the atoms of the solute metal take positions normally occupied by the solvent metal atoms, as they are more or less the same size. In an interstitial alloy, the solute metal atoms occupy the "holes" between the solvent metal atoms. My question is now, which type of alloy is harder and how is this connected to the amount of solute added? I think that interstitial alloys are generally harder and less malleable and ductile than substitutional alloys, as the smaller solute atoms in the holes prevent the ability of the metal cations to slide past each other. Am I right or wrong?
Actually, this was a question that our teacher gave us as homework, but I thought that it was a little poorly worded, so I tried to reword it. But I'm not sure if I understood the task correctly. Maybe someone will understand it, so I took a picture of it: (there are even some grammar mistakes in it and he says alloy A and alloy B, and I thought he means interstitial and substitutional alloys).