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I encountered the fact that $\ce{SO_3}$'s solubility in water is low but even when $\ce{H2S2O7}$ (oleum) is added to water it is $\ce{SO3}$ only that react with water . Please explain the process.

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  • $\begingroup$ What process? The Contact process? $\endgroup$
    – user5764
    Commented Mar 29, 2016 at 14:13
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    $\begingroup$ Solubility of $\ce{SO3}$ in water is not low at all; in fact, they react quite vigorously. $\endgroup$ Commented Mar 29, 2016 at 14:15
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    $\begingroup$ Related: What is the difference between these equations for the Contact process? $\endgroup$
    – user7951
    Commented Mar 29, 2016 at 14:19
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    $\begingroup$ Also see this and this $\endgroup$ Commented Mar 29, 2016 at 15:18

1 Answer 1

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The reaction $\ce{SO_3}$ and $\ce{H_2O}$ is exothermic, which means it releases a lot of heat.The heat produced will boil $\ce{H_2SO_4}$ and become $\ce{H_2SO_4}$ gas. The $\ce{H_2SO_4}$ gas is hard to condense causing this method to be unefficient.

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    $\begingroup$ It would boil water before reaction would end $\endgroup$
    – Mithoron
    Commented Mar 29, 2016 at 19:16

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