I'm doing a titration problem with a week acid and strong base, I used experiment data and an online calculator to check my answer, but my pH I calculated is a bit off. Can anyone see where I messed up? I can't figure out where...
AcOH 0.0984M 0.02500L 0.00246mol Ka 1.8x10^-5
NaOH 0.096M 0.02580L 0.00025mol
0mol AcOH left
0.0025mol - 0.00246mol = 4.0x10^-5 mol OH excess
4.0x10^-5mol OH / 0.0508 L total soln = 7.87x10^-4 M OH-
-log([OH-]) = pOH = 3.104
pH = 10.90
The pH should be 10.52 according to my data and the online calculator.