The answer says that the Bromine would be replaced with OH and NaBr would be formed, along with CH3(CH2)4CH2OH, but why? Does it have to do with stability? And if so, how does the OH replacing Br make the product more stable? Thanks.

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    $\begingroup$ 1-bromohexane does not SN1 $\endgroup$ – Lighthart Mar 25 '16 at 21:25
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    $\begingroup$ NaOH doesn't do SN1 $\endgroup$ – jerepierre Mar 26 '16 at 0:02

SN1 is very less likely to be followed in 1-bromohexane, rather a SN2 pathway will be followed. OH- replaces Br as Br- as Br is a good leaving group. This has nothing to do with product stability. The haloalkane substrate is reactive so it reacts, as simple as that.

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