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I have to find all of the possible canonical structures of this molecule

enter image description here

And here's what I did enter image description here

Are they correct and if yes, did I miss any possibility?

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  • $\begingroup$ These are correct, and I see one more fully octet structure that is closely related to a non-octet structure. $\endgroup$
    – jerepierre
    Commented Mar 23, 2016 at 19:48
  • $\begingroup$ Would it be this one that I've added on the top row? $\endgroup$ Commented Mar 23, 2016 at 19:53
  • $\begingroup$ I added it in the question. $\endgroup$ Commented Mar 23, 2016 at 19:54
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    $\begingroup$ No, in that drawing oxygen has 10 electrons. I would only draw two, to be honest. You're already delocalising a lone-pair on oxygen in one direction. You could also delocalise it in the other direction. $\endgroup$
    – user1160
    Commented Mar 23, 2016 at 19:56
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    $\begingroup$ If oxygen is neutral in the last structure you drew, it would still have 10 electrons. We only observe elements capable of an extended octet in the 3rd period. However, if it has 8 electrons, its charge would be 2+. Oxygen is very electronegative, so that doesn't sound so likely, right? I will post a more detailed answer, or at least resources, a bit later. Meanwhile, please edit your post, so that it doesn't look confusing to someone new coming in. As you did in your original post :-)! $\endgroup$
    – user1160
    Commented Mar 23, 2016 at 20:58

1 Answer 1

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enter image description here

May it look like this? In those two possibles ways?

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    $\begingroup$ Your top row is not possible. Look at the last three rows: there are octet violations $\endgroup$
    – Ben Norris
    Commented Mar 24, 2016 at 1:23
  • $\begingroup$ I don't see how. $\endgroup$ Commented Mar 24, 2016 at 1:29
  • $\begingroup$ And I have done the same things in the bottom row $\endgroup$ Commented Mar 24, 2016 at 1:30
  • $\begingroup$ Oh, you are correct! You have an octet rule violation in the bottom row also. $\endgroup$
    – Ben Norris
    Commented Mar 24, 2016 at 1:32
  • $\begingroup$ But how? Is it because of the triple bond of the oxygen? $\endgroup$ Commented Mar 24, 2016 at 1:33

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