Is the pressure of a gas proportional with the concentration of a gas?

Because you can also use the pressure instead of the concentration in the equilibrium condition.

  • $\begingroup$ What do you call the "concentration" of a gas ? $\endgroup$ – Hippalectryon Mar 19 '16 at 18:04
  • $\begingroup$ @Hippalectryon mol/l? $\endgroup$ – user2997204 Mar 19 '16 at 18:05
  • $\begingroup$ I'm feeling generous: use the ideal gas law. $\endgroup$ – Todd Minehardt Mar 19 '16 at 18:07
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    $\begingroup$ Assuming it follows $PV=nRT$, then if the temperature is fixed then indeed it's proportional to $n/V$ $\endgroup$ – Hippalectryon Mar 19 '16 at 18:07

Assuming your gas follows the ideal gas law, you have $PV=nRT$. Setting $c=\frac nV$ yields $P(c,T)=cRT$.

If the temperature is fixed, then $P(c)=(RT)c$ indeed tells us that the pressure of a gas is proportional to its concentration.


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