# 2nd Electron Affinity of halogens

I have seen questions regarding EA but they were all about the 1st EA so this question is not duplicate.

I came across a statement which goes like "2nd EA of halogens is almost zero". How is this possible? How can energy gained/released on adding an electron be almost 0, particularly when we are adding an electron to a noble gas, because, according to me, a lot of energy is required to do this.

• The $\Delta E$ is nearly zero for addition of a free electron. It will be strongly positive if one is attempting to transfer an electron to $\ce{X^-}$ from some other stable species. – hBy2Py Mar 13 '16 at 18:55