How many electrons are transferred in this redox reaction?

I have the following reaction:

$$\ce{CH_4 (g) + 2O_2 (g) \rightarrow CO_2 (g) + 2H_2 O(l)}$$

How do I determine how many electrons are transferred in this reaction? More specifically, I need to know the value of $v_e$ which I am supposed to plug into the Nernst equation, which my textbook explains as the coefficient of the number of electrons transferred in each half-reaction. How does one go about splitting this into two half-reactions?

• You can post your "I figured it out" part as an answer to this question, you know :) – ManishEarth Apr 22 '13 at 8:07
• Agreed. You should definitely post your answer. – Ben Norris Apr 22 '13 at 11:08