# Product formed under ethoxide/ethanol and heating?

I believe that the first step will be the formation of a radical at the first carbon of the ethyl group because vinyllic radicals are quite stable. However, I'm not really sure what happens after that. The answer key has 'I' as being the correct answer.

• You meant benzylic, rather than vinylic radical, isn't it? – Klaus-Dieter Warzecha Mar 9 '16 at 6:28

The second is simply an $\mathrm{E}2$ $\beta$-elimination reaction, which forms product I: