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When chlorobenzene ($\ce{C6H5Cl}$) reacts with aqueous ($\ce{NaOH}$) solution it first forms sodium phenoxide ($\ce{C6H5ONa}$), and then phenol upon reacting with $\ce{H+}$.

But my question is, why can't $\ce{Na}$ directly replace $\ce{Cl}$ from chlorobenzene by breaking $\ce{Na-O}$ bond instead of breaking $\ce{O-H}$ bond?

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  • $\begingroup$ You mean the Na from the NaOH? $\endgroup$
    – Simon-Nail-It
    Mar 5, 2016 at 9:15
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    $\begingroup$ Can you clarify what you think the mechanism is for this reaction? I don't quite understand your question. $\endgroup$
    – bon
    Mar 5, 2016 at 13:34
  • $\begingroup$ @Simon-Nail-It Yes sir, Na from NaOH $\endgroup$
    – TheNewGenGamer
    Mar 5, 2016 at 15:19
  • $\begingroup$ So your question is why can't $Na^{+}$ react directly with chlorobenzene instead of reacting with phenol? $\endgroup$
    – Rok Narobe
    Mar 5, 2016 at 15:57
  • $\begingroup$ @RokNarobe No sir, i mean to say that why is the long process used when we can just break the C-Cl bond in benzene and then Na+ can react with Cl to form NaCl and phenyl cation can react with OH- to give phenol. Why is Sodium Phenoxide is being formed before giving phenol ? $\endgroup$
    – TheNewGenGamer
    Mar 11, 2016 at 15:04

1 Answer 1

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The mechanism of this reaction is that $\ce{NaOH}$ being a strong base with some extreme conditions abstracts H from C adjacent to C containing Cl while Cl also leaves.

This creates benzyne as an intermediate.

Subsequent addition of $\ce{NaOH}$ forms the phenoxide ion.

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