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Why is the numerical value of a mole of atoms equal to the atomic weight? For example, hydrogen has an atomic weight of 1.008, so 1 mole of hydrogen atoms has a molar mass of 1.008 g/mol. Why?

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closed as unclear what you're asking by Jan, bon, andselisk, Todd Minehardt, Tyberius Oct 25 '17 at 17:39

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If i assumed your question right here is the answer.

1 mole=6.022*10^23 particles (its not any unit of mass)

atomic mass of atoms are often expressed in a unit called amu.

1 amu=1.6605*10^(-24) gram (more significant figures are there)

according to your question

mass of 1 hydrogen atom is 1.008 amu

= 1.008*1.6605*10^(-24) = 1.6737*10^(-24) gram

for 1 mole particles

mass =1.6737*10^(-24) * 6.022*10^(23) = 1.0079 g/mol (approximately 1.008)

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  • $\begingroup$ @user27301 what is that you expect by evidence?(sometimes it may not be upto my level of knowledge to explain in depth) $\endgroup$ – Abhishek Pallippara gopakumar Feb 28 '16 at 15:52
  • $\begingroup$ maybe sources, website if you have any $\endgroup$ – user27301 Feb 28 '16 at 15:54
  • $\begingroup$ @user27301 what proof do you want?I mean about which thing?(that is which part of my answer requires proof ) $\endgroup$ – Abhishek Pallippara gopakumar Feb 28 '16 at 15:56
  • $\begingroup$ @user27301 just multiply those values in calculator and see for yourself. !en.wikipedia.org/wiki/Mole_(unit) Mole is a unit (just like other units) $\endgroup$ – Abhishek Pallippara gopakumar Feb 28 '16 at 16:01
  • $\begingroup$ The rest of the story - The atomic weight in the periodic table isn't for a single isotope, but for the mix of isotopes typical for that element. So chlorine is 75.77% $\ce{^{35}Cl}$ and 24.23% $\ce{^{37}Cl}$. Overall the mixture of isotopes still has $6.022*10^{23}$ atoms. $\endgroup$ – MaxW Feb 28 '16 at 17:54

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