If I have a compound which has non-symmetrical ends, and it has more than one chiral carbon, with no other stereocentres. Then can I say that all of these will be stereocentres, and so there will be 2^n isomers? Can you give an example where this is not true (if)?

  • $\begingroup$ If you have $n$ chiral carbons such that the overall symmetry of the molecule does not make any of them equivalent, then yes, it would be $2^n$. $\endgroup$ – Ivan Neretin Feb 18 '16 at 9:54
  • $\begingroup$ Yes I mean if n is a big number and we can't check all isomers, then how can I tell? I mean, what kind of asymmetry should I look for in the molecule? $\endgroup$ – Shodai Feb 18 '16 at 10:10
  • $\begingroup$ Why would you need to check all isomers to know there are $2^n$ of them (which you already knew before I said that)? $\endgroup$ – Ivan Neretin Feb 18 '16 at 10:21
  • $\begingroup$ I mean, to check if any of them are equivalent. How do I do that? $\endgroup$ – Shodai Feb 18 '16 at 10:23
  • $\begingroup$ Why, just find the point group of your molecule, and you'll see that right away. $\endgroup$ – Ivan Neretin Feb 18 '16 at 10:57

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