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  1. $\ce{C2H6}$ is chlorinated in presence of sunlight to form $\ce{C2H5Cl}$ and $\ce{HCl}$.
  2. $\ce{C2H5Cl}$ is then reacted with water to form $\ce{C2H5OH}$ + $\ce{HCl}$
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  • $\begingroup$ Can someone please confirm this??? $\endgroup$ – Ava Feb 18 '16 at 5:40
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    $\begingroup$ Fundamentally possible, but pretty uneconomic on both stages. $\endgroup$ – Ivan Neretin Feb 18 '16 at 5:42
  • $\begingroup$ @IvanNeretin Especially the first stage. The yield there will be awful. $\endgroup$ – bon Feb 18 '16 at 11:07
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Yes, it is possible.

Although ,commercially(and ironically!) alkyl halides are produced from the corresponding alcohols. The main reason why this is so because free-radical chlorination requires high temperatures and catalysts to promote the reaction.

Theoretically, the first reaction will give good yields(and not a mixture unlike most free radical halogenations because of the simple reactant involved)

Edit:As pointed out by bon, I forgot to take into account that because its a free radical reaction, the number of possible products is a lot.So no, the first reaction will not give you good yields.

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    $\begingroup$ The first reaction will give terrible yields. Multiple chlorinations are highly likely and there is also the possibility of a variety of other radical reactions. $\endgroup$ – bon Feb 18 '16 at 11:13
  • $\begingroup$ :/....I don't know why I didn't take it into account.Thanks for pointing it out :) $\endgroup$ – Karan Singh Feb 18 '16 at 12:30

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