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Does Methyl Iodide ($\ce{CH3I}$) react with water ($\ce{H2O}$) and if it does what would be its byproducts?

A project I am designing requires a reaction with methyl iodide and a polar compound, so I was wondering if methyl iodide reacts with water.

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Methyl iodide is hydrolyzed by water in an $\ce{S_{N}2}$ reaction ($\ce{S_{N}1}$ is disfavored by the instability of the primary methyl cation), which yields methanol and hydroiodic acid as products.

$$\ce{CH3I + H2O <=> CH3OH2^+ + I-}$$ $$\ce{CH3OH2^+ + H2O <=> H3O+ + CH3OH}$$

A possible side reaction is the formation of iodine and methane by the redox reaction

$$\ce{CH3I + H3O+ + I- <=> CH4 + I2 + H2O}$$

However, this reaction becomes only important when a large concentration of methanol pushes the hydrolysis equilibrium to the educt side. It is negligible in pure aqueous solution (reference).

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In common condition, it reacts very slowly and will generate HI and CH3OH. It's soluble. If you don't heat in reaction, I think it's OK. It's very very toxic so take care..

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