The signal at ~3.8ppm is looks like a triplet[t], C-alpha
The signal at ~2.5ppm looks like a triplet of doublets [td], C-gamma.
The signal at ~2.2ppm looks like a doublet of doublet of doublets [ddd], c-beta.
The 2.2 protons are assigned 2.2 because they are the farthest from carbonyls and thus the least deshielded by these functions.
The ddd signal indicates clearly that both protons on C-beta are non-equivalent, because you need 2 3-bond couplings to make a ddd when combined with the 2-bond geminal coupling.
Given the C-beta protons are non-equivalent, the triplet is actually a superimposed doublet of doublets, and the td is actually a similarly superimposed double of doublets [the superimposed-apparent triplet pair and then...] of doublets.