I'm currently reviewing the Periana-Catalytica system and I have a question about one of the intermediates, namely $\ce{[(bpym)Pt(OSO3H)2]^+}$, which is found in the following tutorial review. How do the $\ce{OSO3H}$ ligands affect the oxidation state of the metal? If I count each of these ligands as a monoanionic ligand, and also factor in the positive charge of the complex, wouldn't the oxidation state of the metal be +3? This seems a bit strange to me, seeing as Pt typically has oxidation states of +2 or +4, but never +3.

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    $\begingroup$ wag.caltech.edu/publications/sup/pdf/512.pdf $\endgroup$ – Mithoron Feb 5 '16 at 0:01
  • $\begingroup$ So judging from the complexes I see in Figure 3, I've deduced that $OSO_{3}H$ is a monoanionic ligand. Am I correct? $\endgroup$ – 6nop Feb 5 '16 at 0:56
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    $\begingroup$ Yeah, your right. And there's no problem with intermediate on +3 oxidation. $\endgroup$ – Mithoron Feb 5 '16 at 1:03
  • $\begingroup$ Thank you for clearing that up. So is the +3 oxidation state not really a problem for Pt, per se--it's only not really seen because it's an intermediate and is therefore very transitory? $\endgroup$ – 6nop Feb 5 '16 at 1:07
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    $\begingroup$ There are also Pt (III) compounds, at least dinuclear ones pubs.acs.org/doi/abs/10.1021/ic00137a074 $\endgroup$ – Mithoron Feb 5 '16 at 18:48

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