# How do I figure out the amount of water (mL) and amount of Aluminum (g)?

We have a project where we have to extract copper from copper sulfate. But my group is given a powder version ($5~\mathrm{g}$), so we have to first dilute it with water and then combine it with aluminum to extract the copper. If this is the equation:

$$\ce{3Cu(SO4) + 2Al + H2O + salt -> Al2 (SO4)3 + 3Cu}$$

Salt is acting as a catalyst for the experiment.

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– Jan
Feb 4, 2016 at 20:24

This is simple arithmetic. $$moles = \frac{mass}{molar.weight}$$ The mass of the substance is your measured 5 grams. The molar mass of your compound can be obtained from Wikipedia. In this case, anhydrous copper sulphate has a molar mass of $159.61\frac{g}{mol}$.
Plugging into the equation: 0.0031 $moles = \frac{5}{159.61}$