# Corey-Schmidt oxidation of primary alcohols

Why does pyridinium dichromate (PDC) in dimethylformamide (DMF) oxidize alcohols to acids while in methylene chloride the oxidation stops at the aldehyde level?

As stated in the previously posted answer:

This oxidation into carboxylic acids succeeds when the intermediate aldehyde equilibrates with a liberal proportion of hydrate; that is, when the intermediate aldehyde belongs to the aliphatic kind and is not highly hindered. The water necessary for the formation of the intermediate aldehyde hydrate may proceed from the decomposition of PDC.$^{[1]}$

Though the text does state that water may form from decomposition of the dichromate anion, since DMF is so hygroscopic as a result of its high polarity ($\epsilon_\mathrm{r}=38^{[2]}$), I would not be surprised to learn that little to no over-oxidation occurs in completely dry DMF under an inert atmosphere.

This is only speculation though, and the dichromate anion may very well be decomposing to produce water in the solution. As such, I will propose a reaction mechanism for this decomposition. The first step can only occur when pyridinium dichromate is well solvated and protons are free to be transferred between the species, which occurs in DMF but not in DCM:

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This produces chromic acid, another chromium(VI) oxidizing agent. Unlike dichromate oxidation, however, chromic acid oxidation actually produces water as a byproduct, which is then free to hydrate the resulting aldehydes:

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$[1]$ Tojo, G.; Fernández Marcos. Oxidation of Alcohols to Aldehydes and Ketones: A Guide to Current Common Practice; Springer: New York, NY, 2006; p 28.
$[2]$ Wikipedia: Solvent

I attempt to provide an reasonable answer to this question.

The Corey-Schmidt oxidation uses PDC (pyridinium dichromate) to primarily oxidise alcohols to carbonyl groups. PDC exists in the form of stable bright-orange crystals that remain unaltered by manipulation in the open air. Its lack of hydrophylicity facilitate its handling and allows the selective oxidation of alcohols in the presence of very sensitive functional groups.

The medium generally used is $\ce{CH2Cl2}$, ethyl acetate, benzene, methyl cyanide or chloroform. PDC is far more reactive in more polar solvents like water.

Now, coming to your question the interesting thing is that DMF, which is very efficient in dissolving PDC,causes the over-oxidation of certain alcohols into acids, something that may happen even in the absence of added water.

This oxidation into carboxylic acids succeeds when the intermediate aldehyde equilibrates with a sizeable proportion of hydrate (when the intermediate aldehyde belongs to the aliphatic kind and is not highly hindered). The water necessary for the formation of the intermediate aldehyde hydrate may proceed from the decomposition of PDC.

So given that, it may be concluded that DMF causes PDC to over-oxidise due to following reasons (possible):

1. Decomposition of PDC in DMF to form water molecules, so that hydrate formation of intermediate aldehyde occurs and then conversion into carboxylic acid.

2. This may be aided by the solvation (solubilising) of PDC in DMF.

Reference:

G. Tojo, M. Fernández Oxidation of Alcohols to Aldehydes and Ketones: A Guide to Current Common Practice; Springer Science+Business Media: New York, 2006.

• I would love to see a mechanism of hydrate formation in the absence of water — especially if you postulate it occuring via the dichromate anion. – Jan Jan 25 '16 at 13:17
• With the mechanism I could accept this. – RBW Feb 12 '16 at 19:30