# Color of Anhydrous Transition Metal Salt

Why are some anhydrous transition metal salts colored?

Here are some examples I found.

• Anhydrous cobalt(II) chloride ($\ce{CoCl2}$), with sky-blue color.
• Anhydrous chromium(III) chloride ($\ce{CrCl3}$), with purple color.
• Anhydrous copper(II) chloride ($\ce{CuCl2}$), with yellow-brown color.

I already know that complex ion could undergo d-d transition from its unfilled d orbitals, and that's what makes them pretty-colored. (The wavelength of absorbed light corresponds to the gap in energies between d orbitals.)

But in anhydrous salt, which I think isn't a coordination compound, the d orbitals are degenerate. Thus, no energy gap and excitation could occur, no light is absorbed, and the compound would be colorless / white-colored as it reflects all wavelength.

I summarize my understanding in this problem as below.

• Solution of complex ion could give color (with exception of $\ce{[Zn(H2O)6]^2+}$ and some other complex ions). e.g. $\ce{CuSO4 (aq)}$, which form $\ce{[Cu(H2O)6]^2+}$ complex ion with blue color.
• Hydrated salt is indeed a coordination compound (found related question here), so it could give color. e.g. $\ce{CuSO4.5H2O (s)}$ with blue color.
• Anhydrous salt, because it doesn't have any ligands coordinating with the metal ion, it's not a coordination compound. It's a mere ionic salt instead. Shouldn't it be colorless?

Is there any explanation to this case?

Note that in all compounds mentioned above, the metal ions are transition metal. We don't consider s-block metal ions such as $\ce{NaCl}$ and $\ce{MgSO4}$. (Additional question: They should be colorless, am I right?)

• They are coordination compounds. – Mithoron Jan 24 '16 at 17:39
• The real question is why copper(II) sulphate is colourless in its water-free form. – Jan Jan 25 '16 at 0:50
• @Mithoron I thought ionic salt isn't called coordination compound by definition? – Dean Jan 25 '16 at 17:42
• Most so called salts are more covalent then ionic – Mithoron Jan 26 '16 at 18:04

For anhydrous cobalt(II) chloride, I would immediately expect a closest packing with cobalt ions sitting in tetrahedral voids, occuping ¼ of them to give $\ce{[CoCl4]}$ tetrahedrons where each chloride coordinates two neighbouring cobalt ions. Analogously for chromium(III) chloride, I would expect chromium to occupy one-third of the anion structure’s octahedral voids, giving rise to $\ce{[CrCl6]}$ octahedrons where again each chloride coordinates two chromiums. Both are thus clearly coordination compounds. And going by what I know about $\ce{Cu^{II}}$, that salt will probably be a set of square-planar $\ce{[CuCl4]}$ fragments, again where each chloride coordinates two coppers.