# Reduction of N,N-dimethylbenzamide with LiAlH4

Consider the reaction $$\ce{C6H5CON(CH3)2->[\ce{LiAlH4}]\:\:?}$$

What will the product be?

According to me the product should be $\ce{C6H5CH2OH}$ but I am not sure. Also, I don't have any reasoning for why this must be the product.