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I'm studying ozonolysis reactions in alkenes, and saw that in one of them there is the formation of $\ce{H2O2}$ (Can anyone explain from where?) that I presumed that reacts with $\ce{Zn}$, one of the reagents, as the following: \begin{align} \ce{2H2O2 &-> 2H2O + O2} \\ \ce{2H2O + Zn &-> Zn(OH)2 + H2} \\ \hline \ce{H2O2 + Zn &-> Zn(OH)2} \end{align}

The general reaction is \begin{align} \ce{Unsaturated~compound (-C=C-) + O3 &-> Ozonide\\\\ Ozonide + Zn &-> R^1-(C=O)-R^2 + R^3-(C=O)-R^4 + X} \end{align}

But one of my books shows that this $\ce{X}$ is $\ce{Zn(OH)2}$ only and other $\ce{ZnO}$ only. What about this? What am I doing wrong?

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  • $\begingroup$ Welcome to Chemistry.SE! Take the tour to get familiar with this site. Mathematical expressions and equations can be formatted using $\LaTeX$ syntax.We prefer not to use markup in the title field, see here for details. $\endgroup$ – Martin - マーチン Jan 4 '16 at 6:37
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    $\begingroup$ Your second equation is not balanced: $$\ce{2H2O + Zn -> Zn(OH)2 + H2}$$ Hence $$\ce{H2O2 + Zn -> Zn(OH)2}.$$ $\endgroup$ – Martin - マーチン Jan 4 '16 at 6:44
  • $\begingroup$ @Martin Ooops! Thank you! But $\ce{H2} $ and $\ce{O2}$ will not form water? $\endgroup$ – Vinicius ACP Jan 4 '16 at 7:01
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    $\begingroup$ Well I personally would assume that hydrogen peroxide directly reacts with zinc. So my estimate would be that there is no hydrogen or oxygen formation. It probably depends a lot on the mechanism and your $\ce{X}$ will ultimately depend on how much water and what pH is present. $\endgroup$ – Martin - マーチン Jan 4 '16 at 7:08

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