1
$\begingroup$

If everything is in a mixture of alcohol and water, would it be possible for magnesium chloride and iodine to react and produce something?

$\endgroup$
1
$\begingroup$

Magnesium chloride and Iodine with form an equilibrium. This is a bit of a simplification of the reactions but the dissociated chlorides and free iodine will reversibly react to form iodide and triiodide ions and chlorine.
$$\ce{Cl- + 1/2 I2 <=> 1/2 Cl2 + I-} $$ $$\ce{MgCl2 + I2 <=> MgI2 + Cl2} $$ $$\ce{I- + I2 <=> I3-} $$ $$\ce{MgI2 + 2I <=> Mg(I3)2} $$ The amount of products of this reaction though will not be very appreciable, but yes a very literal sense magnesium chloride and iodine will react.

$\endgroup$
  • 2
    $\begingroup$ $\ce{<=>}$ gives you the correct arrows: $\ce{<=>}$ $\endgroup$ – orthocresol Dec 29 '15 at 2:47
  • 1
    $\begingroup$ what do you mean by not be very appreciable? Could you quantify it generally? $\endgroup$ – intuition Dec 29 '15 at 4:55
  • 2
    $\begingroup$ That would be pretty negligible. On the same grounds you may claim that any two compounds react with each other, which also would be technically true in some sense. $\endgroup$ – Ivan Neretin Dec 29 '15 at 5:52
  • 3
    $\begingroup$ Looking at it macroscopically, the first two equilibria are so far on the reactants’ side, that one would say ‘no reaction is observed’. $\endgroup$ – Jan Dec 29 '15 at 13:06

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.