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When sulfuric acid reacts with copper, then $\ce{H2SO4}$ gives nascent oxygen $\ce{[O]}$. The reaction is: $$\ce{H2SO4 -> H2O + SO2 + [O]}$$

This nascent oxygen reacts with copper to create $\ce{CuO}$.

Therefore my question is that when copper reacts with $\ce{HCl}$ then why doesn’t $\ce{HCl}$ give nascent chlorine $\ce{[Cl]}$ so that it could react with copper and create copper(II) chloride $\ce{CuCl2}$?

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    $\begingroup$ Honourable Sir, please take care to use proper capitalisation in further posts and ensure that your caps lock key does not get stuck halfway through the post. Ye may wish to take a tour of this establishment. Furthermore, I have taken the liberty to improve your correspondence by including MathJax syntax for chemical formulae; ye may learn more about this extraordinary feature in the help center or in the storey us regulars call meta. I hope you enjoy your visit here and may your contributions be qualitative and plentiful. Yours sincerely, $\endgroup$ – Jan Dec 21 '15 at 14:32
  • $\begingroup$ This may be due to standard redox potentials between copper cations and chlorine anions, which can't give the driving force to generate nascent gas $Cl_{2}$, and the high solubility of $CuCl_{2}$ that doesn't allow this salt precipitation. $\endgroup$ – Orr22 Dec 21 '15 at 14:37
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When concentrated sulfuric acid is heated, then it decomposes via the reaction $$\ce{H2SO4 -> H2O + SO3}$$

I tried to determine under what circumstances the nascent oxygen (a free single atom of oxygen) is formed which would react with copper to create $\ce{CuO}$ but couldn't find the reaction in any modern source. I did find the proposed reaction in Essentials of Modern Chemistry By Charles Elwood Dull (1918) but I'm guessing that the reaction to give nascent oxygen is just wrong.

The gist here is that you can't piece reactions together from balanced equations but you must also define the conditions under which the reaction takes place. At a deeper level not only can the chemical equation be specified but also the mechanism of the reaction can be detailed.

Hydrochloric acid, $\ce{HCl}$, is typically in aqueous solution. Although copper won't react with pure hydrochloric acid, it can react with dissolved oxygen in hydrochloric acid. $$\ce{Cu (s) + 2HCl (aq) + 1/2O2 (aq) -> CuCl2 (aq) + H2O}$$

Oxygen can also be formed in chlorine water: $$\begin{align} \ce{Cl2 (aq) &-> HCl + HOCl}\\ \ce{HOCl &-> HCl + 1/2O2} \end{align}$$

But the concept of nacent oxygen from this reaction is wrong.

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    $\begingroup$ FYI: States of aggregation should not be subscripted, it is not wrong, but the recommendations (Sec. 2.1.) are different. I also adjusted the choice of maths environment and removed the blockquoting. $\endgroup$ – Martin - マーチン Jan 4 '16 at 11:05

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