-2
$\begingroup$

Electronic configuration of calcium is $\ce{1s^2 2s^2 2p^6 3s^2 3p^6 4s^2}$. The orbitals are fully filled with electrons so would its valency be two or zero?

$\endgroup$
  • 3
    $\begingroup$ The configuration $$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2$$ has a valency of zero since there are as many electrons as protons. The configuration $$1s^2 2s^2 2p^6 3s^2 3p^6 $$ is two electrons short, so it has a valency of +2. $\endgroup$ – MaxW Dec 17 '15 at 15:34
1
$\begingroup$

Yes, the valency is 2. It's all orbitals are completely filled, but it's outer most orbit is incomplete. Ca can easy donate 2 electrons and can become stable cation.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.