# Reactions of alcohol with sulfuric acid

I knew two chemical reactions of alcohol with sulfuric acid

1. $\ce{CH3CH2OH + H2SO4 -> CH2CH2}$
Here product is having a double bond (ethene) and this reaction happens at 443 K temperature.

2. $\ce{CH3CH2OH + H2SO4 -> C2H5OC2H5}$
Here product is ether an happens at 413 K temperature.

But today I came across another reaction.

1. $\ce{C2H5OH + H2SO4 -> C2H5OSO2OH + H2O}$

Now my question is when will this third reaction happen? Any specific temperature?

The book from which I found this reaction doesn't describe anything. Just says: Alcohols react with inorganic acids (except halogen acids) to form inorganic esters.

• Have you tried searching? en.wikipedia.org/wiki/Organosulfate Dec 7, 2015 at 20:47
• You understand that these are equilibrium reactions, which happen concurrently and lots of things affect those equilibria? Dec 7, 2015 at 21:04
• @Mithoron You mean to say these are three different Major products at different temperatures? Dec 7, 2015 at 21:06
• The organic sulphate should be rather prone to solvolysis and loss of sulphate — at least colleagues of mine have gotten themselves quite a few grey hairs when trying to isolate a sulphate-containing secondary metabolite.
– Jan
Dec 8, 2015 at 13:27

Actually this is the product produces when ethene reacts with sulphuric acid. You can say like that firstly ethyl alcohol coverts to ethene and futher it reacts with sulphuric acid to give $\ce{CH3-CH2-OSO3H}$. It futher reacts with water to give ethyl achohol again at $\pu{100 ^\circ C}$