3
$\begingroup$

Can someone please explain how these compounds are formed/how the 3c 2e comes into existence.

  1. Polymeric structure of BeCl2 - 3c 4e
  2. BeH2 - 3c 2e
  3. CH5+

Please explain in terms of the hybridization of the central atom and how the electrons are shared etc. Thanks!

My approach -

I know that in B2H6 there is a banana bond (3c 2e), but in BH3 it makes more sense - both B go into sp3 hybridization, and one hybrid orbital of each is empty where some overlapping takes place due to the H bonded with the other B, thus causing the electron pair to jump from one B to another. Thus named banana bond. With CH5 I don't understand how C is able to hybridize in a way such that it can have a banana bond. I read that it is of the form CH3 and H2 and 3c 2e bonding in between them, but I don't understand how it takes place. For BeCl2 there are 2 Be having 2 Cls each and also coordinate bond by other 2 chlorines. Is that right? But for BeH2, how can there be a 3c 2e bond? I mean based on the same principle, there must be a bond between Be, H that can jump to the other Be with same H, but Be doesn't have enough electrons to do this. Thus my confusion.

$\endgroup$

closed as too broad by jerepierre, Jan, Todd Minehardt, ron, ringo Dec 7 '15 at 23:49

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

Browse other questions tagged or ask your own question.