-1
$\begingroup$

The equation for the burning of octane:

$$\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}$$

  1. How do i find the number of moles of carbon dioxide which is produced when one mole of octane burns ?
  2. How do i find , at what volume , at STP , is occupied by the number of moles determined in the answer to my first question ?
  3. If the relative molecular mass of carbon dioxide is 44 , what is the mass of carbon dioxide produced by burning 2 moles of octane?
$\endgroup$

closed as off-topic by orthocresol, Jan, Todd Minehardt, Loong, Martin - マーチン Nov 18 '15 at 15:13

This question appears to be off-topic. The users who voted to close gave this specific reason:

If this question can be reworded to fit the rules in the help center, please edit the question.

1
$\begingroup$

This is a homework problem, so I'll not spell the answer outright, but try and give as much as I would if you came to me in office hours.

  1. Your equation tells you what the ratio of moles of $\ce{C8H18}$ to moles of $\ce{CO2}$. For every two moles of octane burned, how many moles of $\ce{CO2}$ are produced? Now, what would it be for only one mole of octane?

  2. What have you tried so far on this? You have the ideal gas law (PV = nRT), and you know the P, the n from the first question, and the T - so just solve for the V.

  3. So you know one mole of $\ce{CO2}$ masses 44 grams, so just multiply this by the number of moles of $\ce{CO2}$ produced by 2 moles of octane (see my hint on point 1 above).

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.