# Is it possible to express Gibbs free energy as following?

We know $$\Delta G =\Delta H -T\Delta S$$ $$\Delta S= \frac{Q_{rev}}{T}$$ Hence $$\Delta G=\Delta H-Q_{rev}$$

• Yes... It is possible. But a better question for me to ask is: why would you not think it's possible? – orthocresol Nov 4 '15 at 8:31