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We know $$\Delta G =\Delta H -T\Delta S$$ $$\Delta S= \frac{Q_{rev}}{T} $$ Hence $$\Delta G=\Delta H-Q_{rev} $$

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  • $\begingroup$ Yes... It is possible. But a better question for me to ask is: why would you not think it's possible? $\endgroup$ – orthocresol Nov 4 '15 at 8:31
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Yes, but only if the temperature T in the initial and final equilibrium states of the system is the same and you are able to identify a reversible path between the initial and final equilibrium states over which all the heat transfer takes place at the temperature T.

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