1
$\begingroup$

When a gas under a high pressure in a piston (isolated from surrounding is allowed to pass through a valve), why does its temperature decrease once during expansion?

I haven't still studied thermodynamics but would like to know why exactly the temperature decreases.

Is it because under high pressure the heat was concentrated under small volume once expanded the heat is distributed?

Once the gas molecules are allowed to expand through the valve its kinetic energy increases. Where is the source of energy coming from, is it from its internal energy?

$\endgroup$
1

1 Answer 1

1
$\begingroup$

In order to expand, the molecules may do work, such as pushing against a piston, pushing against the container (as in water rockets), spinning a turbine, etc. Energy is transferred from molecular motion to another form, so the temperature drops.

In free expansion, however,

the gas does no work and absorbs no heat, so the internal energy is conserved. Expanded in this manner, the temperature of an ideal gas would remain constant, but the temperature of a real gas may either increase or decrease, depending on the initial temperature and pressure.

[from Wikipedia].

$\endgroup$
4
  • $\begingroup$ If a real gas undergoes a free expansion, energy must be supplied in order to overcome the attractive forces which are not neglected in this case, this energy comes from the internal energy of the molecules. As a result, the molecules temperature decreases. What about the ideal gas, where does the energy come from in order to pass through the valve?. $\endgroup$
    – Abmon98
    Nov 6, 2015 at 12:44
  • $\begingroup$ No, no energy is applied from outside: the kinetic energy of the molecules is the source. See the demo at youtube.com/watch?v=tEFHkcx2cz0 $\endgroup$ Nov 8, 2015 at 2:20
  • $\begingroup$ What i have realised from the idea once the gas(blue) expands its temperature drops, because it uses some of its internal energy (kinetic in this case) thus its temperature drops. $\endgroup$
    – Abmon98
    Nov 8, 2015 at 7:31
  • $\begingroup$ What about real gases? $\endgroup$
    – Abmon98
    Nov 8, 2015 at 7:35

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.