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The valence electron configuration of $\ce{Cu}$ is $\ce{4s^1 3d^{10}}$. According to this the answer is $11$, but shouldn't it be $1$ since the d shell is already filled up?

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Yes, copper only has 1 valence electron. Remember: valence electrons only include the electrons in the highest energy (n) shell.

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    $\begingroup$ How does it form Cu(II) then? $\endgroup$ – orthocresol♦ Oct 29 '15 at 9:57

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