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How many next nearest neighborhood respectively each potassium has in bcc lattice?

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closed as off-topic by Jan, M.A.R., ron, bon, Todd Minehardt Oct 29 '15 at 0:02

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  • $\begingroup$ I am just not able to proceed, I know how to find first nearest neighbours but don't know how to find second nearest neighbors $\endgroup$ – ashwini abhishek Oct 28 '15 at 17:31
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    $\begingroup$ Well, second nearest neighbors are the neighbors of the first nearest neighbors, not counting those that are already first nearest. You get there by looking at one unit cell of bcc and imagining the next unit cells out and which atom(s) in those cells are closest. $\endgroup$ – Jon Custer Oct 28 '15 at 17:41
  • $\begingroup$ BCC is the very case when the distinction between "first nearest" and "second nearest" does not work really well. However, a line still can be drawn between the two. How many first nearest neighbors did you find, to begin with? $\endgroup$ – Ivan Neretin Oct 28 '15 at 17:45
  • $\begingroup$ You're overthinking the problem. I'll give you a hint. I paint one particular "molecule" of potassium red. How many atoms are in a "molecule" of potassium metal? How many nearest neighbors does my red "molecule" have? $\endgroup$ – MaxW Oct 28 '15 at 18:37
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    $\begingroup$ I find 8 first nearest atoms $\endgroup$ – ashwini abhishek Oct 28 '15 at 19:06
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Second nearest neighbors are the neighbors of the first neighbors. So for BCC let's consider the atom at the body centre, for this atom the atom at the corner are nearest and for the atoms at the corners the atom at body centres of other cubes are nearest. Little imagination(there are 6 body centred atoms surrounding the atom we are considering) and counting gives the answer as six.

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