Please explain using only enolisation and protonation steps:
My workings so far:
Seems completely wrong... Can someone please correct me?
*i just proposed a new mechanism:
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After Step 2, re-protonate alpha to the carbonyl (the double bond has now migrated to the beta-gamma position). Now enolize the carbonyl - remove the proton next to the methyl group (the top one), then push the electrons all the way back, protonating the gamma position. Job done!