Arrange the following in decreasing order of acidity
I think it's S>P>R>Q
(Q) forms an anti aromatic conjugate base. So its the least acidic compound here.
(R) forms forms a conjugate base which is only stabilized by electron withdrawing (inductive) effect of $\ce{S}$.
(P) forms an aromatic conjugate base and (S) forms am ion stabilised by resonance (two resonance structures). But negative charge in $\ce{O}$ is more stable than negative charge on $\ce{C}$. So (S)>(P).
Is this correct?