# Why does magnesium oxide not react with water?

There is a question in my textbook which asks "which of the reactions are not possible to occur". The right answer is $$\ce{MgO + H2O}$$ and my chemistry teacher confirmed it. Why is that so? I thought that it would form $$\ce{Mg(OH)2}$$.

Does the reactivity also depend on the temperature?

• MgO has a high lattice energy of about 4000 KJ/mol. Also MgO is insoluble in water because the atoms are tightly held. MgO has a rock salt structure. Oct 13, 2015 at 13:43
• That's true, but hardly explains anything. Again, CaO has the same structure. Oct 13, 2015 at 15:53
• I'm inactive at this time, and regardless wouldn't be able to answer the question with sufficient rigor it deserves. Perhaps it is of some help to note that an older Russian textbook blames the apparent lack of reaction on the formation of almost insoluble (probably denser as well) passivating layer of $\ce{Mg(OH)2}$. Calcium hydroxide is more soluble (by some 2500 times, I think, near room temperature). Obviously, this simply pushes the comparison from the oxides to their hydroxides (to some extent) which might be of limited use. Oct 30, 2018 at 18:24

Like a lot of things in chemistry, "it depends".

Magnesium oxide is commonly produced by calcination of magnesium hydroxide or carbonate. The magnesium hydroxide or carbonate decomposes at a fairly low temperature whereas magnesium oxide is itself stable to both decomposition and melting beyond 2000°C. So, we can choose from a wide range of calcining temperature, and as explained here we can use this to dial in the reactivity we want.

At a low calcining temperature the magnesia is quite reactive, even hygroscopic (the "magnesium oxide" film formed on magnesium in ambient air is thus usually magnesium hydroxide); this "light-burned magnesia" is used where easy reactivity is required as in water or soil treatment. And, yes, the reaction with water gives magnesium hydroxide.

Calcination at higher temperature gives less reactive "hard-burned" magnesia, or in the extreme case the totally unreactive "dead-burned magnesia" used in furnace refractories.

First off, to not overlook the obvious, both reactions ares thermodynamically favored.

$$\ce{MgO (s) + H2O (l) -> Mg(OH)2 (aq)} \\ \Delta G_\pu{298K}^\circ = \pu{-833.7 kJ mol-1 -( -569.3 kJ mol-1 + -306.7 kJ mol-1) = - 42.3 kJ mol-1}$$

$$\ce{CaO (s) + H2O (l) -> Ca(OH)2 (aq)} \\ \Delta G_\pu{298K}^\circ = \pu{-(-754.2 kJ mol-1 + -306.7 kJ mol-1) + -1011.7 kJ mol-1 = - 49.2 kJ mol-1}$$

Thus thermodynamics is not the reason and thus kinetics must be to blame. For starters combusted magnesium is going to produce partially amorphous $$\ce{MgO}$$ which will reduce the activation energy to hydrolyze magnesium oxide, but why is it that solid magnesium oxide reacts slowly with water allowing me to use crucibles made of the stuff, while calcium oxide reacts quite vigorously despite both being thermodynamically favored?

I believe the answer is in the Cation-anion radius ration (C/A ratio). The C/A ratio for $$\ce{Mg^2+}:\ce{O^2-}$$ is $$0.683$$ ($$\pu{86pm: 126pm}$$) which correspond to a 6-fold nearest neighbors configuration while the C/A ratio for $$\ce{Ca^2+}:\ce{O^2-}$$ is $$0.905$$ ($$\pu{114pm: 126pm}$$) which corresponds to an 8-fold nearest neighbors configuration. Yet both compounds are in a rock salt 6-fold nearest neighbors configuration. AS a result the oxygens of magnesium oxide are tightly packed "touching" each other while the oxygens of calcium oxide are space apart farther than two ionic radii. This allows the oxygen atoms of calcium oxide to "make room" for water and increase the coordination of $$\ce{Ca^2+}$$ to accommodate the additional atoms whereas the oxygens in magnesium cannot.

magnesium forms a layer of $\ce{MgO}$ readily on it's surface when exposed to air, thus preventing further reaction, when you put $\ce{Mg}$ in water, which is actually the $\ce{Mg}$ with the $\ce{MgO}$ crest on it, it is essentially inert to water as the oxide crest won't react, and or allow access to the interior where pure $\ce{Mg}$ lies. But if it were pure $\ce{Mg}$ and Water, the result sure will be $\ce{Mg(OH)2}$

Also for a reaction to occur between a solid and liquid, atoms of the solid need to dissolve on the liquid to interact with the liquid itself or a component of liquid as a mixture. It is a fact that $\ce{MgO}$ is not very soluble in water, hence restricting it's interaction with water

In response to comment by Ivan Neretin

IvanNeretin @IvanNeretin , the solubility of $\ce{MgO}$ is $\pu{0.0086g/100mL}$ while $\ce{CaO}$ reacts directly with water, it is the natural property of $\ce{MgO}$ to not to react with water, while $\ce{CaO}$ naturally reacts with water. I can deduce one thing from this $\ce{MgO}$ is stable in water, while as $\ce{CaO}$ is instable, and reacts to form a stable a stable $\ce{Ca(OH)2}$

• This doesn't explain why MgO doesn't react with water. Oct 13, 2015 at 11:34
• That still leaves much of the question open. See, $\ce{CaO}$ is almost the same as $\ce{MgO}$ (would anyone call it soluble?), but it reacts with water quite vigorously. Oct 13, 2015 at 12:08