# At what temperature will 6 grams of KMnO4 saturate 100 grams of water

I am trying to obtain more $\ce{KMnO4}$ from less amount by crystallization method. If I got the temperature I would easily make the desired amount. If I am choosing the wrong method, please tell me the correct one. I have 10 grams of potassium permanganate.

• You got a aqueous KMnO4 solution, right? – AstronAUT Sep 28 '15 at 16:16
• When you say "obtain more...from less" I am interpreting this to mean: use a small amount of crystalline KMnO4 to seed a supersaturated water solution of that substance and help it to crystallize out. Is that right? – iad22agp Sep 28 '15 at 16:34

Solubility of $\ce{KMnO4}$ at 20 °C: $6.34~\mathrm{g/100~g}$ water
Solubility of $\ce{KMnO4}$ at 10 °C: $4.31~\mathrm{g/100~g}$ water
interpolation gives: $6.00~\mathrm{g/100~g}$ water at approximately 18.3 °C.