The question is something like this: 2g of a metal is present in 4.6g of its metal sulphate. Find the equivalent weight of the metal.
I understand the concept that equivalent weight of an element is the molecular weight divided by the n-factor(in this case its the valency) , but I couldn't arrive at a conclusion. Could you also help me understand how equivalent weight of a metal is related to the equivalent weight of the sulphate. In my textbook, its written like this:
Eq.Wt. of metal =(equivalent to) Eq.Wt. of metal sulhpate(2-)
and then they carried on with the calculations... PS- I know the answer, I need to know how one should conceptually arrive at it!