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The question is something like this: 2g of a metal is present in 4.6g of its metal sulphate. Find the equivalent weight of the metal.

I understand the concept that equivalent weight of an element is the molecular weight divided by the n-factor(in this case its the valency) , but I couldn't arrive at a conclusion. Could you also help me understand how equivalent weight of a metal is related to the equivalent weight of the sulphate. In my textbook, its written like this:

Eq.Wt. of metal =(equivalent to) Eq.Wt. of metal sulhpate(2-)

and then they carried on with the calculations... PS- I know the answer, I need to know how one should conceptually arrive at it!

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I assume that if you are dealing in equivalent weights then you must be well associated with the concepts of equivalents . Now, E equivalent = weight / eq. Weight And since compounds combine in equal amounts of equivalents we have Weight of metal / eq weight = weight of sulphate / its eq weight 2/x = 2.6/48 Hence x= 39.92

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