While I was trying to draw a possible representation of $\ce{(CH3O)2CH=CHCH(OCH3)2}$ I was perplexed by the fact that from left to right the second carbon atom has a double bound with the third one, while at the same time it is connected to two methyl groups, plus the H element. That makes five bounds. I found this as an answer:


But in my opinion, in the image, the double bound is misplaced as it should be on the from the first carbon atom after O. I am stuck here.

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    $\begingroup$ The formula you have there is impossible because as you recognized, there is a carbon with five bonds. $\endgroup$ – bon Sep 24 '15 at 19:49
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    $\begingroup$ @pigeon Your condensed formula corresponds to $\ce{C7H15O4}$, whereas your structural formula corresponds to $\ce{C8H16O4}$. $\endgroup$ – Loong Sep 24 '15 at 19:57
  • $\begingroup$ That's right, the molecule is symmetric around the double bond, and so should be the formula. One CH is missing. $\endgroup$ – Ivan Neretin Sep 24 '15 at 19:57
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    $\begingroup$ Yes that is right . i did not notice this one! It is a mistake made in the book i am reading from. $\endgroup$ – pigeon Sep 24 '15 at 20:05
  • $\begingroup$ Also the structure you have drawn has 8 carbons but the formula you give only has 7. $\endgroup$ – Curt F. Sep 24 '15 at 20:34

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