What effect does temperature have on endothermic and exothermic reversible reactions? (Please also mention the reason why it happens like this)

And what do people mean by doing something like increasing pressure or volume the reaction shifts to left/right? What do people mean by left/right reaction shift?

  • $\begingroup$ When asking a homework question it's expected that you'll include your own thoughts on the question you're asking. I would suggest reading this question and its answers, which address your left/right question. For temperature and endo/exothermic reactions, it helps to consider heat to be one of the reactants or products. $\endgroup$ – Jason Patterson Sep 20 '15 at 16:19

In a reaction, there is an exothermic and a endothermic side. Increasing the temperature will favour the endothermic side.

So if your reaction is exothermic, that means it must release heat if it shifts to the left. Then, since the left is exothermic, it shifts to the right (endothermic) to minimise this disturbance.

If your reaction is endothermic, that means it must absorb heat if it shits to the left. Then, since the left is endothermic, if you increase the temperature it shifts to the left (endothermic) to minimise this disturbance.

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The above is much easier to understand if you think of 'heat' as a product or reactant. In an exothermic reaction, heat is on the product side of the equation. So if you increase this component, to minimise this disturbance you must shift the equilibrium to the LEFT to decrease the 'heat' amount - and vice versa.

  • $\begingroup$ Thank You silenceislife very much. The idea of thinking heat as product is very useful. $\endgroup$ – Dimenein Sep 26 '15 at 16:21
  • $\begingroup$ And also thanks to this question chemistry.stackexchange.com/questions/5486/… I understood shift in equilbrium properly. $\endgroup$ – Dimenein Sep 26 '15 at 16:29

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